(C) According to Kohlrausch's law,the molar conductance at infinite dilution for $NH_4OH$ can be calculated as:$\Lambda^{o}_{m}(NH_4OH) = \Lambda^{o}_

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(C) According to Kohlrausch's law,the molar conductance at infinite dilution for $NH_4OH$ can be calculated as:$\Lambda^{o}_{m}(NH_4OH) = \Lambda^{o}_{m}(NH_4Cl) + \Lambda^{o}_{m}(Ba(OH)_2) \times \frac{1}{2} - \Lambda^{o}_{m}(BaCl_2) \times \frac{1}{2}$Substituting the given values:$\Lambda^{o}_{m}(NH_4OH) = 129.8 + (523.28 \times 0.5) - (280.0 \times 0.5)$$= 129.8 + 261.64 - 140.0$$= 391.44 - 140.0 = 251.44 \ \Omega^{-1} \ cm^2 \ mol^{-1}$

Class 12 Chemistry Electrochemistry Conductor and Conductance and Cell constant

Medium

What will be the molar conductance at infinite dilution for $NH_4OH$ if at infinite dilution the molar conductances of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively?

A
$502.88$
B
$373.68$
C
$251.44$
D
$226.96$

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Conductor and Conductance and Cell constant

The resistance of a $0.2 \, M$ electrolyte solution is $50 \, \Omega$. The specific conductivity of the solution is $1.3 \, S \, m^{-1}$. If the resistance of a $0.4 \, M$ solution of the same electrolyte is $260 \, \Omega$,what is its molar conductivity?

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In a conductivity cell,the electrodes are separated by a distance of $2 \ cm$ and have a cross-sectional area of $4 \ cm^2$. If the conductivity of pure water is $8 \times 10^{-7} \ S \ cm^{-1}$,then the resistance of the water is:

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What will be the molar conductance at infinite dilution for $NH_4OH$ if at infinite dilution the molar conductances of $Ba(OH)_2$,$BaCl_2$,and $NH_4Cl$ are $523.28$,$280.0$,and $129.8 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively?

Similar Questions

The resistance of a $0.2 \, M$ electrolyte solution is $50 \, \Omega$. The specific conductivity of the solution is $1.3 \, S \, m^{-1}$. If the resistance of a $0.4 \, M$ solution of the same electrolyte is $260 \, \Omega$,what is its molar conductivity?

If the specific conductivity of $0.1 \, N$ nitric acid is $6.2 \times 10^{-2} \, \Omega^{-1} \, cm^{-1}$,what will be the molar conductivity of the solution in $\Omega^{-1} \, cm^{2} \, mol^{-1}$?

In a conductivity cell,the electrodes are separated by a distance of $2 \ cm$ and have a cross-sectional area of $4 \ cm^2$. If the conductivity of pure water is $8 \times 10^{-7} \ S \ cm^{-1}$,then the resistance of the water is:

The factor which is not affecting the conductivity of any solution is

Explain Kohlrausch law of independent migration of ions.

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