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(B) To find the equivalent resistance of $\frac{22}{3} \, \Omega$,we test the given options.For option $A$: Parallel combination of $A$ and $C$ is $R_

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Parallel combination of $A$ and $B$ connected in series with $C$.

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(B) To find the equivalent resistance of $\frac{22}{3} \, \Omega$,we test the given options.For option $A$: Parallel combination of $A$ and $C$ is $R_{p} = \frac{A 	imes C}{A + C} = \frac{2 	imes 6}{2 + 6} = \frac{12}{8} = 1.5 \, \Omega$.Adding $B$ in series: $R_{eq} = R_{p} + B = 1.5 + 4 = 5.5 \, \Omega$.For option $B$: Parallel combination of $A$ and $B$ is $R_{p} = \frac{A 	imes B}{A + B} = \frac{2 	imes 4}{2 + 4} = \frac{8}{6} = \frac{4}{3} \, \Omega$.Adding $C$ in series: $R_{eq} = R_{p} + C = \frac{4}{3} + 6 = \frac{4 + 18}{3} = \frac{22}{3} \, \Omega$.Thus,the correct combination is the parallel combination of $A$ and $B$ connected in series with $C$.

What will be the most suitable combination of three resistors $A = 2 \, \Omega$,$B = 4 \, \Omega$,$C = 6 \, \Omega$ so that $\frac{22}{3} \, \Omega$ is the equivalent resistance of the combination?

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