What will be the reduction products of the following reactions:
$CHCl_3 \xrightarrow[Zn/HCl \text{ (alc.)}]{+2H}$
$CHCl_3 \xrightarrow[Zn/HCl \text{ (aq.)}]{+4H}$
$CHCl_3 \xrightarrow[Zn/H_2O]{+6H}$

  • A
    $CH_2Cl_2, CH_3Cl, CH_4$
  • B
    $CH_4, CH_3Cl, CH_2Cl_2$
  • C
    $CH_3Cl, CH_2Cl_2, CH_4$
  • D
    $CH_3Cl, CH_4, CH_2Cl_2$

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