What will be the theoretical value of magneti | vedclass

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(D) The electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.For $Fe^{3+}$,the configuration is $[Ar] 3d^5$.$CN^-$ is a strong field ligand,w

Vedclass · Accepted Answer

$1.73$

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(D) The electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.For $Fe^{3+}$,the configuration is $[Ar] 3d^5$.$CN^-$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.In $Fe^{3+}$ $(3d^5)$,the five electrons are paired such that four electrons form two pairs and one electron remains unpaired $(n=1)$.The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.

What will be the theoretical value of magnetic moment $(\mu)$ when $CN^-$ ligands join $Fe^{3+}$ ion to yield a complex (in $BM$)?

Similar Questions

Choose the complexes which are paramagnetic from the following:
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