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(B) First,convert the mixed fractions into improper fractions:$5 \frac{17}{37} = \frac{5 	imes 37 + 17}{37} = \frac{185 + 17}{37} = \frac{202}{37}$$4

Vedclass · Accepted Answer

$305.75$

Vedclass · Answer

(B) First,convert the mixed fractions into improper fractions:$5 \frac{17}{37} = \frac{5 	imes 37 + 17}{37} = \frac{185 + 17}{37} = \frac{202}{37}$$4 \frac{51}{52} = \frac{4 	imes 52 + 51}{52} = \frac{208 + 51}{52} = \frac{259}{52}$$11 \frac{1}{7} = \frac{11 	imes 7 + 1}{7} = \frac{77 + 1}{7} = \frac{78}{7}$$2 \frac{3}{4} = \frac{2 	imes 4 + 3}{4} = \frac{8 + 3}{4} = \frac{11}{4}$Now,substitute these into the expression:$? = \frac{202}{37} 	imes \frac{259}{52} 	imes \frac{78}{7} + \frac{11}{4}$Simplify the multiplication:$= \frac{202}{37} 	imes \frac{259}{7} 	imes \frac{78}{52} + \frac{11}{4}$$= \frac{202}{37} 	imes 37 	imes \frac{3}{2} + \frac{11}{4}$$= 202 	imes \frac{3}{2} + \frac{11}{4}$$= 101 	imes 3 + 2.75$$= 303 + 2.75 = 305.75$

What will come in place of the question mark (?) in the following expression?
$5 \frac{17}{37} \times 4 \frac{51}{52} \times 11 \frac{1}{7} + 2 \frac{3}{4} = ?$

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What will come in place of the question mark (?) in the following expression?$5 \frac{17}{37} \times 4 \frac{51}{52} \times 11 \frac{1}{7} + 2 \frac{3}{4} = ?$