What will come in the place of the question m | vedclass

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(D) To find the value of $?$,we rearrange the equation:$? = 2 \frac{1}{8} - 1 \frac{1}{16} - 1 \frac{1}{32} + 1 \frac{9}{64}$Separate the whole number

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$1 \frac{11}{64}$

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(D) To find the value of $?$,we rearrange the equation:$? = 2 \frac{1}{8} - 1 \frac{1}{16} - 1 \frac{1}{32} + 1 \frac{9}{64}$Separate the whole numbers and the fractions:$? = (2 - 1 - 1 + 1) + (\frac{1}{8} - \frac{1}{16} - \frac{1}{32} + \frac{9}{64})$Calculate the whole number part:$2 - 1 - 1 + 1 = 1$Calculate the fractional part by finding the common denominator,which is $64$:$\frac{1}{8} - \frac{1}{16} - \frac{1}{32} + \frac{9}{64} = \frac{8}{64} - \frac{4}{64} - \frac{2}{64} + \frac{9}{64}$$= \frac{8 - 4 - 2 + 9}{64} = \frac{11}{64}$Combining both parts,we get:$? = 1 + \frac{11}{64} = 1 \frac{11}{64}$

What will come in the place of the question mark $(?)$ in the following equation?
$2 \frac{1}{8} - 1 \frac{1}{16} = ? + 1 \frac{1}{32} - 1 \frac{9}{64}$

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What will come in the place of the question mark $(?)$ in the following equation?$2 \frac{1}{8} - 1 \frac{1}{16} = ? + 1 \frac{1}{32} - 1 \frac{9}{64}$