(B) Let the first term be $a$ and the common difference be $d$. The $n^{th}$ term is $T_n = a + (n-1)d$.Given $T_9 = 5T_2$ $\Rightarrow a + 8d = 5(a +

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(B) Let the first term be $a$ and the common difference be $d$. The $n^{th}$ term is $T_n = a + (n-1)d$.Given $T_9 = 5T_2$ $\Rightarrow a + 8d = 5(a + d)$ $\Rightarrow a + 8d = 5a + 5d$ $\Rightarrow 4a - 3d = 0$ $\Rightarrow d = \frac{4a}{3}$.Given $T_{13} = 2T_6 + 5$ $\Rightarrow a + 12d = 2(a + 5d) + 5$ $\Rightarrow a + 12d = 2a + 10d + 5$ $\Rightarrow 2d - a = 5$.Substitute $d = \frac{4a}{3}$ into the second equation: $2(\frac{4a}{3}) - a = 5$.$\frac{8a}{3} - a = 5$ $\Rightarrow \frac{5a}{3} = 5$ $\Rightarrow a = 3$.

Class 11 Mathematics Sequences and Series Arithmetic progression

When the $9^{th}$ term of an $A.P.$ is divided by its $2^{nd}$ term,the quotient is $5$. When the $13^{th}$ term is divided by the $6^{th}$ term,the quotient is $2$ and the remainder is $5$. Find the first term of the $A.P.$

A
$2$
B
$3$
C
$4$
D
$5$

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Sequences and Series

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Arithmetic progression

Given the sum of the first $n$ terms of an $A.P.$ is $S_n = 2n + 3n^2$. Another $A.P.$ is formed with the same first term and double the common difference. The sum of $n$ terms of the new $A.P.$ is:

DifficultJEE MAIN 2013

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Given that $n$ arithmetic means are inserted between two sets of numbers $(a, 2b)$ and $(2a, b)$, where $a, b \in \mathbb{R}$. Suppose the $m^{th}$ means between these sets are equal, then the ratio $a : b$ is equal to:

MediumWBJEE 2018

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If $A_1, A_2$ are the two $A.M.'s$ between two numbers $a$ and $b$ and $G_1, G_2$ are two $G.M.'s$ between the same two numbers,then $\frac{A_1 + A_2}{G_1 G_2} = $

Easy

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Let $a_1, a_2, a_3, \ldots, a_{100}$ be an arithmetic progression with $a_1=3$ and $S_p=\sum_{i=1}^p a_i, 1 \leq p \leq 100$. For any integer $n$ with $1 \leq n \leq 20$,let $m=5n$. If $\frac{S_m}{S_n}$ does not depend on $n$,then $a_2$ is

IIT 2011

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The sum of the common terms of the following three arithmetic progressions:
$3, 7, 11, 15, \ldots, 399$
$2, 5, 8, 11, \ldots, 359$ and
$2, 7, 12, 17, \ldots, 197$,is equal to $................$.

DifficultJEE MAIN 2023

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When the $9^{th}$ term of an $A.P.$ is divided by its $2^{nd}$ term,the quotient is $5$. When the $13^{th}$ term is divided by the $6^{th}$ term,the quotient is $2$ and the remainder is $5$. Find the first term of the $A.P.$

Similar Questions

Given the sum of the first $n$ terms of an $A.P.$ is $S_n = 2n + 3n^2$. Another $A.P.$ is formed with the same first term and double the common difference. The sum of $n$ terms of the new $A.P.$ is:

Given that $n$ arithmetic means are inserted between two sets of numbers $(a, 2b)$ and $(2a, b)$, where $a, b \in \mathbb{R}$. Suppose the $m^{th}$ means between these sets are equal, then the ratio $a : b$ is equal to:

If $A_1, A_2$ are the two $A.M.'s$ between two numbers $a$ and $b$ and $G_1, G_2$ are two $G.M.'s$ between the same two numbers,then $\frac{A_1 + A_2}{G_1 G_2} = $

Let $a_1, a_2, a_3, \ldots, a_{100}$ be an arithmetic progression with $a_1=3$ and $S_p=\sum_{i=1}^p a_i, 1 \leq p \leq 100$. For any integer $n$ with $1 \leq n \leq 20$,let $m=5n$. If $\frac{S_m}{S_n}$ does not depend on $n$,then $a_2$ is

The sum of the common terms of the following three arithmetic progressions:$3, 7, 11, 15, \ldots, 399$$2, 5, 8, 11, \ldots, 359$ and$2, 7, 12, 17, \ldots, 197$,is equal to $................$.

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The sum of the common terms of the following three arithmetic progressions:
$3, 7, 11, 15, \ldots, 399$
$2, 5, 8, 11, \ldots, 359$ and
$2, 7, 12, 17, \ldots, 197$,is equal to $................$.