When 9.65 A current was passed for 1.0 h in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total charge passed is $Q = I 	imes t = 9.65 \ A 	imes 3600 \ s = 34740 \ C$.Number of moles of electrons passed $= \frac{Q}{F} = \frac{3474

Vedclass · Accepted Answer

$9.81$

Vedclass · Answer

(C) The total charge passed is $Q = I 	imes t = 9.65 \ A 	imes 3600 \ s = 34740 \ C$.Number of moles of electrons passed $= \frac{Q}{F} = \frac{34740 \ C}{96500 \ C/mol} = 0.36 \ mol$.The reduction of nitrobenzene to $p$-aminophenol involves $4$ electrons:$C_6H_5NO_2 + 4H^+ + 4e^- 	o HOC_6H_4NH_2 + H_2O$.Since $4 \ mol$ of electrons produce $1 \ mol$ of $p$-aminophenol,$0.36 \ mol$ of electrons will produce $\frac{0.36}{4} = 0.09 \ mol$ of $p$-aminophenol.The molar mass of $p$-aminophenol $(C_6H_7NO)$ is $109.13 \ g/mol$.Mass of $p$-aminophenol $= 0.09 \ mol 	imes 109.13 \ g/mol = 9.82 \ g \approx 9.81 \ g$.

When $9.65 \ A$ current was passed for $1.0 \ h$ into nitrobenzene in an acidic medium,the amount of $p$-aminophenol produced is .............. $g$.

Similar Questions

What amount of electricity can deposit $1 \ mole$ of $Al$ metal at cathode when passed through molten $AlCl_3$?

How many amperes must be passed through a Down's cell to produce sodium metal at a rate of $30.0 \ kg/h$?

The quantity of silver deposited when one coulomb charge is passed through $AgNO_3$ solution:

$0.066 \ g$ of metal was deposited when a current of $2 \ A$ is passed through a metal ion solution for $100 \ s$. What is the electrochemical equivalent (in $g \ C^{-1}$) of the metal?

When electricity is passed through a solution of $AlCl_3$,$13.5 \ g$ of $Al$ is deposited. What is the number of Faradays used?

Vedclass Test Series

Exam Paper Generator

Online Exam Module