When $NaNO_3$ is heated in a closed vessel,$O_2$ is liberated and $NaNO_2$ is left behind. At equilibrium,

  • A
    Addition of $NaNO_3$ favours forward reaction
  • B
    Addition of $NaNO_2$ favours reverse reaction
  • C
    Increasing pressure favours reverse reaction
  • D
    All of the above

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For the reaction $X_{2(g)} + 4Y_{2(g)} \rightleftharpoons 2XY_{4(g)}$,$\Delta H < 0$. According to which of the following factors is the yield of the product favored?

Higher yield of $NO$ in $N_{2(g)} + O_{2(g)} \rightleftharpoons 2 NO_{(g)}$ can be obtained at [ $\Delta H$ of the reaction $= +180.7 \ kJ \ mol^{-1}$ ]
$A.$ Higher temperature
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$C.$ Higher concentration of $N_2$
$D.$ Higher concentration of $O_2$
Choose the correct answer from the options given below:

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