When 40 , mL of 0.1 , N , HCl and 20 , mL of | vedclass

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(B) The normality of $HCl$ is $N_1 = 0.1 \, N$ and volume is $V_1 = 40 \, mL$.For $H_2SO_4$,the molarity is $M = 0.1 \, M$. The n-factor for $H_2SO_4$

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$\frac{2}{15} \, N$

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(B) The normality of $HCl$ is $N_1 = 0.1 \, N$ and volume is $V_1 = 40 \, mL$.For $H_2SO_4$,the molarity is $M = 0.1 \, M$. The n-factor for $H_2SO_4$ is $2$,so its normality is $N_2 = M 	imes 	ext{n-factor} = 0.1 	imes 2 = 0.2 \, N$. The volume is $V_2 = 20 \, mL$.The formula for the normality of the mixture is $N_R = \frac{N_1 V_1 + N_2 V_2}{V_1 + V_2}$.Substituting the values: $N_R = \frac{0.1 	imes 40 + 0.2 	imes 20}{40 + 20}$.$N_R = \frac{4 + 4}{60} = \frac{8}{60} = \frac{2}{15} \, N$.

When $40 \, mL$ of $0.1 \, N \, HCl$ and $20 \, mL$ of $0.1 \, M \, H_2SO_4$ are mixed together,the normality of the mixture will be

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