When $SO_3$ is treated with heavy water,the product is:

  • A
    Deuterium and sulphuric acid
  • B
    Deuterium and sulphurous acid
  • C
    Only deuterium
  • D
    Dideuterosulphuric acid

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Assertion $(A)$ : $NaCl$ is less soluble in heavy water than in ordinary water.
Reason $(R)$ : Dielectric constant of ordinary water is more than that of heavy water.
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