When 335 is added to 5A7, the result is 8B2. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the addition: $5A7 + 335 = 8B2$Looking at the units place: $7 + 5 = 12$, so the last digit is $2$ and there is a carry of $1$ to the tens pl

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) Given the addition: $5A7 + 335 = 8B2$Looking at the units place: $7 + 5 = 12$, so the last digit is $2$ and there is a carry of $1$ to the tens place.Looking at the tens place: $A + 3 + 1 = B$ (where $1$ is the carry from the units place).So, $A + 4 = B$.Looking at the hundreds place: $5 + 3 = 8$, which matches the result.Since $8B2$ is divisible by $3$, the sum of its digits must be a multiple of $3$:$8 + B + 2 = 10 + B = 	ext{multiple of } 3$.Possible values for $B$ are $2, 5, 8$.Case $1$: If $B = 2$, then $A + 4 = 2 \Rightarrow A = -2$ (Not possible as $A$ is a digit).Case $2$: If $B = 5$, then $A + 4 = 5 \Rightarrow A = 1$.Case $3$: If $B = 8$, then $A + 4 = 8 \Rightarrow A = 4$.The largest possible value of $A$ is $4$.

When $335$ is added to $5A7$, the result is $8B2$. $8B2$ is divisible by $3$. What is the largest possible value of $A$?

Similar Questions

On dividing a number by $38$, we get $90$ as quotient and $19$ as remainder. What is the number?

$\frac{16}{24} + \frac{4}{10} - \frac{1}{6} = ?$

The sum of nine consecutive odd numbers of Set $A$ is $621$. What is the sum of a different set of six consecutive even numbers whose lowest number is $15$ more than the lowest number of Set $A$?

The sum of three numbers is $264$. If the first number is twice the second and the third number is one-third of the first,then the second number is:

$A$ fraction is greater than its reciprocal by $\frac{9}{20}$. What is the fraction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module