When H_2S gas is passed through a hot acidic | vedclass

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(D) The correct answer is $D$. When $H_2S$ gas is passed through an acidic solution,only group $II$ cations precipitate as their sulfides because the

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$PbS$ and $CuS$

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(D) The correct answer is $D$. When $H_2S$ gas is passed through an acidic solution,only group $II$ cations precipitate as their sulfides because the low concentration of $S^{2-}$ ions (due to the common ion effect of $H^+$) is sufficient to exceed the solubility product $(K_{sp})$ of group $II$ sulfides. Among the given ions,$Cu^{2+}$ and $Pb^{2+}$ belong to group $II$. $Al^{3+}$ belongs to group $III$ and $Ni^{2+}$ belongs to group $IV$,which do not precipitate in acidic medium. The reactions are: $Cu^{2+} + H_2S \longrightarrow CuS(s) + 2H^+$ $Pb^{2+} + H_2S \longrightarrow PbS(s) + 2H^+$

When $H_2S$ gas is passed through a hot acidic aqueous solution containing $Al^{3+}$,$Cu^{2+}$,$Pb^{2+}$ and $Ni^{2+}$,a precipitate is formed,which consists of

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