When KI is reacted with O_3 under aqueous con | vedclass

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Question

(D) When ozone $(O_3)$ reacts with potassium iodide $(KI)$ in an aqueous medium,it acts as an oxidizing agent. The chemical reaction is: $2 KI_{(aq)}

Vedclass · Accepted Answer

$I_2$

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(D) When ozone $(O_3)$ reacts with potassium iodide $(KI)$ in an aqueous medium,it acts as an oxidizing agent. The chemical reaction is: $2 KI_{(aq)} + H_2O_{(l)} + O_{3(g)} \rightarrow 2 KOH_{(aq)} + I_{2(s)} + O_{2(g)}$ The ionic form of this reaction is: $2 I^{-}_{(aq)} + H_2O_{(l)} + O_{3(g)} \rightarrow 2 OH^{-}_{(aq)} + I_{2(s)} + O_{2(g)}$ Thus,the product formed is iodine $(I_2)$.

When $KI$ is reacted with $O_3$ under aqueous condition,the product formed is:

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