When a DC voltage of 200, V is applied to a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For $DC$ supply,the inductor acts as a simple resistor because $X_L = 2\pi fL$ and $f = 0$. Thus,$R = \frac{V}{I_1} = \frac{200}{1} = 200\,\Omega$

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(D) For $DC$ supply,the inductor acts as a simple resistor because $X_L = 2\pi fL$ and $f = 0$. Thus,$R = \frac{V}{I_1} = \frac{200}{1} = 200\,\Omega$.For $AC$ supply,the impedance $Z$ is given by $Z = \frac{V}{I_2} = \frac{200}{0.5} = 400\,\Omega$.The impedance of an $RL$ circuit is $Z = \sqrt{R^2 + X_L^2}$.Substituting the values: $400 = \sqrt{200^2 + X_L^2}$.Squaring both sides: $160000 = 40000 + X_L^2$,which gives $X_L^2 = 120000$.$X_L = \sqrt{120000} = 200\sqrt{3}\,\Omega$.Since $X_L = 2\pi fL$,we have $200\sqrt{3} = 2\pi f \left( \frac{2\sqrt{3}}{\pi} \right)$.$200\sqrt{3} = 4\sqrt{3} f$.$f = \frac{200\sqrt{3}}{4\sqrt{3}} = 50\,Hz$.

When a $DC$ voltage of $200\, V$ is applied to a coil of self-inductance $\frac{2\sqrt{3}}{\pi}\,H$,a current of $1\, A$ flows through it. When the $DC$ source is replaced by an $AC$ source of $200\, V$,the current in the coil is reduced to $0.5\, A$. The frequency of the $AC$ supply is......$Hz$.

Similar Questions

An inductor and a resistor are connected in series to an ac source of variable frequency. When the frequency of the applied ac is $50 \ Hz$,the power factor of the circuit is $\frac{\sqrt{3}}{2}$. If the frequency of the ac is increased by $200 \%$,the power factor of the circuit is . . . . . . .

The adjoining figure shows an $AC$ circuit with resistance $R$,inductance $L$ and source voltage $V_s$. Then

In the given circuit, the r.m.s. value of the current through the resistor $R$ is:

In an $RC$ $AC$ circuit,the maximum voltage and maximum current are $100 \ V$ and $1.1 \ A$ respectively. If $X_{C} = 60 \ \Omega$ and $R = 80 \ \Omega$,then the power consumed in the circuit will be . . . . . . . (in $W$)

$A$ resistance of $200 \ \Omega$ and an inductor of $\frac{1}{2 \pi} \ H$ are connected in series to an a.c. voltage of $40 \ V$ and $100 \ Hz$ frequency. The phase angle between the voltage and current is

Vedclass Test Series

Exam Paper Generator

Online Exam Module