When a concentrated solution of sulphanilic a | vedclass

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Question

(C) The reaction involves the diazotization of sulphanilic acid followed by coupling with $1-$naphthylamine to form a red-azo dye (Congo Red derivativ

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(C) The reaction involves the diazotization of sulphanilic acid followed by coupling with $1-$naphthylamine to form a red-azo dye (Congo Red derivative).Step $1$: Sulphanilic acid $(C_6H_7NO_3S)$ reacts with $HNO_2$ to form a diazonium salt.Step $2$: The diazonium salt couples with $1-$naphthylamine $(C_{10}H_9N)$ to form the azo dye $(C_{16}H_{13}N_3O_3S)$.The molecular formula of the product is $C_{16}H_{13}N_3O_3S$.Molar mass $= (16 	imes 12) + (13 	imes 1) + (3 	imes 14) + (3 	imes 16) + (1 	imes 32) = 192 + 13 + 42 + 48 + 32 = 327 \ g \ mol^{-1}$.Mass of $0.1 \ mole$ of product $= 0.1 \ mol 	imes 327 \ g \ mol^{-1} = 32.7 \ g$.Rounding to the nearest integer,the mass is $33 \ g$.

When a concentrated solution of sulphanilic acid and $1-$naphthylamine is treated with nitrous acid $(273 \ K)$ and acidified with acetic acid,the mass $(g)$ of $0.1 \ mole$ of product formed is : (Given molar mass in $g \ mol^{-1} H: 1, C: 12, N: 14, O: 16, S: 32$)

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