When a metal X is treated with cold water,it | vedclass

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Question

(A) $(i)$ The molecular formula of $Y$ is $XOH$ and its molecular mass is $40$. The atomic mass of $O$ is $16$ and $H$ is $1$. Thus,$X + 16 + 1 = 40$,

Vedclass · Accepted Answer

$X = Na, Y = NaOH, Z = H_2$

Vedclass · Answer

(A) $(i)$ The molecular formula of $Y$ is $XOH$ and its molecular mass is $40$. The atomic mass of $O$ is $16$ and $H$ is $1$. Thus,$X + 16 + 1 = 40$,which gives $X = 23$. The element with atomic mass $23$ is Sodium $(Na)$.$(ii)$ When sodium $(Na)$ reacts with cold water,it forms sodium hydroxide $(NaOH)$ and releases hydrogen gas $(H_2)$.$(iii)$ Hydrogen gas $(H_2)$ is highly flammable and catches fire easily.$(iv)$ Therefore,$X = Na$,$Y = NaOH$,and $Z = H_2$.

When a metal $X$ is treated with cold water,it gives a basic salt $Y$ with molecular formula $XOH$ (Molecular mass $= 40$) and liberates a gas $Z$ which easily catches fire. Identify $X, Y, Z$.

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