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(D) The force on a charged particle moving in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.Case $(1)$

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any one of $(1)$, $(2)$ and $(3)$

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(D) The force on a charged particle moving in a magnetic field is given by the Lorentz force formula: $\vec{F} = q(\vec{v} 	imes \vec{B})$.Case $(1)$: If the velocity $\vec{v}$ is parallel or anti-parallel to the magnetic field $\vec{B}$, then $\vec{v} 	imes \vec{B} = 0$. The force is zero, and the particle continues in a straight line.Case $(2)$: If the velocity $\vec{v}$ is perpendicular to the magnetic field $\vec{B}$, the magnetic force acts as a centripetal force, causing the particle to move in a circle.Case $(3)$: If the velocity $\vec{v}$ makes an angle $	heta$ (where $	heta 
eq 0^\circ, 90^\circ, 180^\circ$) with the magnetic field $\vec{B}$, the velocity can be resolved into two components: one parallel to $\vec{B}$ (causing linear motion) and one perpendicular to $\vec{B}$ (causing circular motion). The resultant trajectory is a helix.Therefore, all three trajectories are possible depending on the angle between the velocity and the magnetic field.

When a positively charged particle enters a uniform magnetic field with uniform velocity, its trajectory can be:
$(1)$ a straight line
$(2)$ a circle
$(3)$ a helix

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When a positively charged particle enters a uniform magnetic field with uniform velocity, its trajectory can be:$(1)$ a straight line$(2)$ a circle$(3)$ a helix