When a ray of light is incident normally on one refracting surface of an equilateral prism (Refractive index of the material of the prism $= 1.5$),what happens to the ray at the second refracting surface?

Consider the following statements for the refraction of light through a prism,when the angle of deviation is minimum.
$(A)$ The refracted ray inside the prism becomes parallel to the base.
$(B)$ Larger angle prisms provide smaller angle of minimum deviation.
$(C)$ The angle of incidence and the angle of emergence become equal.
$(D)$ There are always two sets of angles of incidence for which the deviation will be the same,except at the minimum deviation setting.
$(E)$ The angle of refraction becomes double the prism angle.
Choose the correct answer from the options given below.

$A$ prism is made of glass of unknown refractive index. $A$ parallel beam of light is incident on a face of the prism. The angle of minimum deviation is measured to be $40^{\circ}$. What is the refractive index of the material of the prism? The refracting angle of the prism is $60^{\circ}$. If the prism is placed in water (refractive index $1.33$),predict the new angle of minimum deviation of a parallel beam of light.

The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Let $D_1$ and $D_2$ be the angles of deviation for red and blue light,respectively,in a prism of this glass. Then:

An equilateral prism is placed on a horizontal surface. $A$ ray $PQ$ is incident onto it. For minimum deviation:

$A$ flint glass prism and a crown glass prism are to be combined in such a way that the deviation of the mean ray is zero. The refractive indices of flint and crown glasses for the mean ray are $1.620$ and $1.518$ respectively. If the refracting angle of the flint prism is $6.0^{\circ}$,what would be the refracting angle of the crown prism (in $^{\circ}$)?