When a satellite going round the Earth in a circular orbit of radius $r$ and speed $v$ loses some of its energy,then $r$ and $v$ change as:

The energy required to take a satellite to a height $h$ above the Earth's surface (radius of Earth $R = 6.4 \times 10^3 \, km$) is $E_1$,and the kinetic energy required for the satellite to be in a circular orbit at this height is $E_2$. The value of $h$ for which $E_1 = E_2$ is:

$A$ satellite has kinetic energy $K$, potential energy $V$, and total energy $E$. Which of the following statements is true?

Given below are two statements:
Statement $I:$ If $E$ be the total energy of a satellite moving around the earth,then its potential energy will be $\frac{E}{2}$.
Statement $II:$ The kinetic energy of a satellite revolving in an orbit is equal to the half the magnitude of total energy $E$.
In the light of the above statements,choose the most appropriate answer from the options given below.

$A$ satellite is orbiting the Earth with an orbital velocity $v_0$. If it is suddenly stopped and allowed to fall onto the Earth,what will be its velocity when it hits the Earth's surface? (Let $v_e$ be the escape velocity from the Earth's surface.)

$A$ satellite moving around the Earth in a circular orbit has kinetic energy '$E$'. What is the minimum amount of energy to be added so that it escapes from the Earth?