When acidified $K_2Cr_2O_7$ reacts with $H_2O_2$,a blue-coloured solution is obtained. This blue colour is due to the formation of:

  • A
    $Cr_2O_3$
  • B
    $CrO_3$
  • C
    $Cr_2(SO_4)_3$
  • D
    $CrO_5$

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