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(A) The torque $\vec{	au}$ acting on an electric dipole placed in a uniform electric field is given by the cross product: $\vec{	au} = \vec{P} 	ime

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(A) The torque $\vec{	au}$ acting on an electric dipole placed in a uniform electric field is given by the cross product: $\vec{	au} = \vec{P} 	imes \vec{E}$.The magnitude of the torque is given by $	au = PE \sin 	heta$,where $	heta$ is the angle between the dipole moment vector $\vec{P}$ and the electric field vector $\vec{E}$.For the torque to be maximum,$\sin 	heta$ must be maximum.The maximum value of $\sin 	heta$ is $1$,which occurs when $	heta = 90^{\circ}$.Therefore,the torque is maximum when the angle between $\vec{P}$ and $\vec{E}$ is $90^{\circ}$.

When an electric dipole $\overrightarrow{P}$ is placed in a uniform electric field $\overrightarrow{E}$,at what angle between $\overrightarrow{P}$ and $\overrightarrow{E}$ will the magnitude of the torque be maximum? (in degrees)

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