When connected across the terminals of a cell | vedclass

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Question

(B) The voltmeter reading across the terminals of the cell when the ammeter is connected represents the terminal voltage $V$ when the current $I = 10\

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(B) The voltmeter reading across the terminals of the cell when the ammeter is connected represents the terminal voltage $V$ when the current $I = 10\,A$ is drawn. However,in this context,the cell is providing $10\,A$ through the ammeter. Assuming the ammeter has negligible resistance,the $EMF$ $E$ of the cell is $5\,V$. The internal resistance $r$ is given by $r = \frac{V}{I} = \frac{5\,V}{10\,A} = 0.5\,\Omega$.When an external resistance $R = 2\,\Omega$ is connected across the terminals,the total resistance of the circuit becomes $R_{total} = R + r = 2\,\Omega + 0.5\,\Omega = 2.5\,\Omega$.The current $i$ flowing through this resistance is given by Ohm's law: $i = \frac{E}{R_{total}} = \frac{5\,V}{2.5\,\Omega} = 2\,A$.

When connected across the terminals of a cell,a voltmeter measures $5\,V$ and a connected ammeter measures $10\,A$ of current. $A$ resistance of $2\,\Omega$ is connected across the terminals of the cell. The current flowing through this resistance will be ............ $A$.

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