When an electron jumps from n = 5 to n = 2 wi | vedclass

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(D) The number of spectral lines emitted when an electron jumps from $n_2$ to $n_1$ is given by the formula $\frac{(n_2 - n_1)(n_2 - n_1 + 1)}{2}$.For

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All of these

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(D) The number of spectral lines emitted when an electron jumps from $n_2$ to $n_1$ is given by the formula $\frac{(n_2 - n_1)(n_2 - n_1 + 1)}{2}$.For $n_2 = 5$ and $n_1 = 2$,the total number of lines is $\frac{(5 - 2)(5 - 2 + 1)}{2} = \frac{3 	imes 4}{2} = 6$.The possible transitions are:$5 	o 4, 5 	o 3, 5 	o 2, 4 	o 3, 4 	o 2, 3 	o 2$.$1$. Ultraviolet region (Lyman series,$n_1 = 1$): None of these transitions end at $n = 1$,so the number of lines is $0$.$2$. Visible region (Balmer series,$n_1 = 2$): The transitions ending at $n = 2$ are $5 	o 2, 4 	o 2, 3 	o 2$. Total lines = $3$.$3$. Infrared region (Paschen series,$n_1 = 3$): The transitions ending at $n = 3$ are $5 	o 3, 4 	o 3$. Total lines = $2$.Since none of the individual statements $A, B, C$ are correct,and option $D$ claims all are correct,there is an error in the provided options. However,based on standard textbook problems of this type,if the question implies transitions ending at $n=2$,the visible lines are $3$. Given the options,the question is flawed.

When an electron jumps from $n = 5$ to $n = 2$ with all possible transitions,which of the following statements is correct?

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