When is the force between atoms attractive? When is it repulsive?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The force between atoms depends on the distance $r$ between them relative to the equilibrium distance $r_0$ (where potential energy is minimum).
$1$. The force is repulsive when the distance between atoms is less than the equilibrium distance $(r < r_0)$. In this region,the electron clouds of the atoms overlap,leading to strong electrostatic repulsion.
$2$. The force is attractive when the distance between atoms is greater than the equilibrium distance $(r > r_0)$. In this region,the interatomic potential energy increases as $r$ increases,and the atoms experience an attractive force pulling them back toward the equilibrium position.

Explore More

Similar Questions

If the length of a wire is doubled,what is the strain?

The elastic behaviour of a material for linear stress and linear strain is shown in the figure. The energy density for a linear strain of $5 \times 10^{-4}$ is $\dots \; kJ/m^3$. Assume that the material is elastic up to the linear strain of $5 \times 10^{-4}$.

Pressure and stress have the same unit (and dimension),although they are not the same physical quantity. Why?

The shear strain is possible in .............

According to $C.E.$ van der Waals,the interatomic potential varies with the average interatomic distance $(R)$ as

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo