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(B) The number of photoelectrons ejected is directly proportional to the intensity of the incident light. Therefore, if the intensity is doubled from

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$2N$ and $K$

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(B) The number of photoelectrons ejected is directly proportional to the intensity of the incident light. Therefore, if the intensity is doubled from $I$ to $2I$, the number of photoelectrons emitted will also double, becoming $2N$.Maximum kinetic energy $(K)$ of the photoelectrons is determined by Einstein's photoelectric equation: $K = h
u - \Phi$, where $h$ is Planck's constant, $
u$ is the frequency of incident radiation, and $\Phi$ is the work function of the metal.Since the frequency $
u$ remains unchanged, the maximum kinetic energy $K$ remains constant regardless of the change in intensity.Thus, the new values are $2N$ and $K$.

When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectrons and their maximum kinetic energy are $N$ and $K$ respectively. If the intensity of radiation is $2I$, the number of emitted electrons and their maximum kinetic energy are respectively

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