When potassium permanganate is titrated again | vedclass

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Question

(B) In the titration of potassium permanganate $(KMnO_4)$ with ferrous ammonium sulphate (Mohr's salt),the reaction occurs in an acidic medium.$KMnO_4

Vedclass · Accepted Answer

Molecular weight / $5$

Vedclass · Answer

(B) In the titration of potassium permanganate $(KMnO_4)$ with ferrous ammonium sulphate (Mohr's salt),the reaction occurs in an acidic medium.$KMnO_4$ acts as an oxidizing agent and $Fe^{2+}$ acts as a reducing agent.The reduction half-reaction for $KMnO_4$ in acidic medium is: $MnO_4^- + 8H^+ + 5e^- ightarrow Mn^{2+} + 4H_2O$.The change in oxidation state of $Mn$ is from $+7$ to $+2$,so the $n$-factor is $5$.The equivalent weight of an oxidizing agent is defined as: $	ext{Equivalent weight} = \frac{	ext{Molecular weight}}{n	ext{-factor}}$.Therefore,the equivalent weight of $KMnO_4$ is $\frac{	ext{Molecular weight}}{5}$.

When potassium permanganate is titrated against ferrous ammonium sulphate,the equivalent weight of potassium permanganate is

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