When sulphur is boiled with Na_2SO_3,a compou | vedclass

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Question

(A) The reaction of sulphur $(S)$ with sodium sulphite $(Na_2SO_3)$ produces sodium thiosulphate $(Na_2S_2O_3)$,which is compound $(A)$.$S + Na_2SO_3

Vedclass · Accepted Answer

$Na_2S_2O_3, Ag_2S_2O_3, Ag_2S$

Vedclass · Answer

(A) The reaction of sulphur $(S)$ with sodium sulphite $(Na_2SO_3)$ produces sodium thiosulphate $(Na_2S_2O_3)$,which is compound $(A)$.$S + Na_2SO_3 \rightarrow Na_2S_2O_3 (A)$When $Na_2S_2O_3$ reacts with excess $AgNO_3$,it forms silver thiosulphate $(Ag_2S_2O_3)$,which is compound $(B)$.$Na_2S_2O_3 + 2AgNO_3 \rightarrow Ag_2S_2O_3 (B) + 2NaNO_3$Finally,$Ag_2S_2O_3$ decomposes in water to form a black precipitate of silver sulphide $(Ag_2S)$,which is compound $(C)$.$Ag_2S_2O_3 + H_2O \rightarrow Ag_2S (C) + H_2SO_4$Thus,the correct sequence is $(A) = Na_2S_2O_3$,$(B) = Ag_2S_2O_3$,and $(C) = Ag_2S$.

When sulphur is boiled with $Na_2SO_3$,a compound $(A)$ is produced. $(A)$ on reaction with excess $AgNO_3$ solution gives a compound $(B)$,which after dissolving in water produces a black coloured sulphide $(C)$. Identify the compound $(A)$,$(B)$ and $(C)$.

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