When the angle of incidence is 60^{circ} on t | vedclass

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(B) According to Brewster's Law,when the reflected ray is completely polarized,the angle of incidence is equal to the polarizing angle $(	heta_p)$.Gi

Vedclass · Accepted Answer

$\sqrt{3} 	imes 10^{8} 	ext{ m/s}$

Vedclass · Answer

(B) According to Brewster's Law,when the reflected ray is completely polarized,the angle of incidence is equal to the polarizing angle $(	heta_p)$.Given,$	heta_p = 60^{\circ}$.The refractive index of glass $(\mu_g)$ is given by $\mu_g = 	an 	heta_p$.$\mu_g = 	an 60^{\circ} = \sqrt{3}$.We know that the refractive index is the ratio of the speed of light in vacuum $(c)$ to the speed of light in the medium $(v_g)$:$\mu_g = \frac{c}{v_g}$.Substituting the values,$\sqrt{3} = \frac{3 	imes 10^8 	ext{ m/s}}{v_g}$.$v_g = \frac{3 	imes 10^8}{\sqrt{3}} 	ext{ m/s} = \sqrt{3} 	imes 10^8 	ext{ m/s}$.

When the angle of incidence is $60^{\circ}$ on the surface of a glass slab,it is found that the reflected ray is completely polarized. The velocity of light in glass is

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