When the distance between the slit and the screen is doubled,what happens to the angular separation between the fringes in a slit diffraction experiment?

In a Fraunhofer diffraction due to a single slit,the diffraction pattern is formed on the focal plane of a lens of focal length $f = 1 \ m$. The width of the slit is $a = 0.3 \ mm$. If the third minimum is formed at a distance of $5 \ mm$ from the central maximum,find the wavelength of light in $\mathring{A}$.

Define diffraction.

Light of wavelength $5000 \text{ Å}$ is incident normally on a slit. The first minimum of the diffraction pattern is observed to lie at a distance of $5 \text{ mm}$ from the central maximum on a screen placed at a distance of $2 \text{ m}$ from the slit. The width of the slit is: (in $\text{ cm}$)

When you look at a clear blue sky, you see tiny specks and hair-like structures floating in your view, called "floaters". This is basically

Orange light of wavelength $6000 \times 10^{-10} \ m$ illuminates a single slit of width $0.6 \times 10^{-4} \ m$. The maximum possible number of diffraction minima produced on both sides of the central maximum is $........$