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(A) The magnifying power of a compound microscope is given by the formula $|m| = \frac{v_o}{u_o} 	imes \frac{D}{u_e}$.Here,$v_o$ is the image distanc

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Decreases

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(A) The magnifying power of a compound microscope is given by the formula $|m| = \frac{v_o}{u_o} 	imes \frac{D}{u_e}$.Here,$v_o$ is the image distance from the objective lens,$u_o$ is the object distance from the objective lens,$D$ is the least distance of distinct vision,and $u_e$ is the object distance from the eyepiece.The length of the microscope tube $L$ is given by $L = v_o + u_e$.For a fixed objective lens position,if the tube length $L$ is increased,the distance $u_e$ between the eyepiece and the intermediate image must increase.Since the magnifying power $m$ is inversely proportional to $u_e$ (as $m \propto \frac{1}{u_e}$),an increase in $u_e$ leads to a decrease in the magnifying power.

When the length of a microscope tube increases,its magnifying power

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