When the object is self-luminous,the resolving power of a microscope is given by the expression

  • A
    $\frac{2\mu \sin \theta}{1.22 \lambda}$
  • B
    $\frac{\mu \sin \theta}{\lambda}$
  • C
    $\frac{2\mu \cos \theta}{1.22 \lambda}$
  • D
    $\frac{2\mu}{\lambda}$

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