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Question

(A) The wave number $\bar{
u}$ is given by the Rydberg formula: $\bar{
u} = R \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} ight]$.Here,the electron tr

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$109700$

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(A) The wave number $\bar{
u}$ is given by the Rydberg formula: $\bar{
u} = R \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} ight]$.Here,the electron transitions from infinity $(n_2 = \infty)$ to the first orbit $(n_1 = 1)$.Substituting these values: $\bar{
u} = R \left[ \frac{1}{1^2} - \frac{1}{\infty^2} ight] = R 	imes (1 - 0) = R$.The Rydberg constant $R$ is approximately $1.097 	imes 10^7 \ m^{-1}$.Converting this to $cm^{-1}$: $R = 1.097 	imes 10^7 	imes 10^{-2} \ cm^{-1} = 1.097 	imes 10^5 \ cm^{-1} = 109700 \ cm^{-1}$.

When the wave of a hydrogen atom comes from infinity into the first orbit,then the value of the wave number is......$cm^{-1}$

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