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(B) Let the capacity of each capacitor be $C$.Three capacitors of capacity $C$ are connected in parallel. Their equivalent capacity is $C_p = C + C +

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$6$

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(B) Let the capacity of each capacitor be $C$.Three capacitors of capacity $C$ are connected in parallel. Their equivalent capacity is $C_p = C + C + C = 3C$.This combination is connected in series with another capacitor of capacity $C$.The equivalent capacity $C_{eq}$ of the series combination is given by:$\frac{1}{C_{eq}} = \frac{1}{C_p} + \frac{1}{C} = \frac{1}{3C} + \frac{1}{C} = \frac{1+3}{3C} = \frac{4}{3C}$.Therefore,$C_{eq} = \frac{3C}{4}$.Given $C_{eq} = 4.5 \mu F$,we have:$4.5 = \frac{3C}{4}$$C = \frac{4.5 	imes 4}{3} = 1.5 	imes 4 = 6 \mu F$.

When three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)

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