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(B) In a parallel combination of resistors,the equivalent resistance $(R_{eq})$ is given by the formula: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{

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Less than $5 \Omega$

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(B) In a parallel combination of resistors,the equivalent resistance $(R_{eq})$ is given by the formula: $\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$.Substituting the given values: $\frac{1}{R_{eq}} = \frac{1}{5} + \frac{1}{10} + \frac{1}{30}$.Finding the common denominator $(30)$: $\frac{1}{R_{eq}} = \frac{6 + 3 + 1}{30} = \frac{10}{30} = \frac{1}{3}$.Therefore,$R_{eq} = 3 \Omega$.In a parallel circuit,the equivalent resistance is always less than the smallest individual resistance present in the circuit. Since the smallest resistance is $5 \Omega$,the equivalent resistance must be less than $5 \Omega$.

When three resistors of $5 \Omega$,$10 \Omega$,and $30 \Omega$ are connected in parallel in a circuit,what will be the equivalent resistance?

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