When treated with conc. HCl,MnO_2 yields a ga | vedclass

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(C) The correct option is $C$.When $MnO_2$ is treated with conc. $HCl$,it produces chlorine gas $(X)$ as follows:$MnO_2 + 4HCl \rightarrow MnCl_2 + Cl

Vedclass · Accepted Answer

$Ca(OCl)Cl$

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(C) The correct option is $C$.When $MnO_2$ is treated with conc. $HCl$,it produces chlorine gas $(X)$ as follows:$MnO_2 + 4HCl \rightarrow MnCl_2 + Cl_2(g) + 2H_2O$Here,$X = Cl_2$.Chlorine gas reacts with dry slaked lime $Ca(OH)_2$ to form bleaching powder,which is calcium oxychloride $Ca(OCl)Cl$ $(Y)$:$Ca(OH)_2 + Cl_2 \rightarrow Ca(OCl)Cl + H_2O$Here,$Y = Ca(OCl)Cl$.Bleaching powder $(Y)$ reacts with dilute $HCl$ to regenerate chlorine gas $(X)$:$Ca(OCl)Cl + 2HCl \rightarrow CaCl_2 + H_2O + Cl_2(g)$

When treated with conc. $HCl$,$MnO_2$ yields a gas $(X)$ which further reacts with $Ca(OH)_2$ to generate a white solid $(Y)$. The solid $Y$ reacts with dil. $HCl$ to produce the same gas $X$. The solid $Y$ is

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