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(C) Let the initial volume be $V_{i}$ and the initial temperature be $T_{i}$.From the ideal gas law,the initial pressure is $P_{i} = \frac{n R T_{i}}{

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(C) Let the initial volume be $V_{i}$ and the initial temperature be $T_{i}$.From the ideal gas law,the initial pressure is $P_{i} = \frac{n R T_{i}}{V_{i}}$.Given that the final volume $V_{f} = 2 V_{i}$ and the final temperature $T_{f} = \frac{T_{i}}{2}$.The final pressure $P_{f}$ is given by $P_{f} = \frac{n R T_{f}}{V_{f}}$.Substituting the values,we get $P_{f} = \frac{n R (T_{i} / 2)}{2 V_{i}} = \frac{1}{4} \left( \frac{n R T_{i}}{V_{i}} \right)$.Therefore,$P_{f} = \frac{1}{4} P_{i} = 0.25 P_{i}$.Thus,the pressure becomes $0.25$ times the initial pressure.

When the volume of a system is increased two times and the temperature is decreased to half of its initial temperature,then the pressure becomes ...... times.

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