Which among the following isomers of C_4H_9OH | vedclass

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(C) The boiling point of isomeric alcohols depends on the extent of branching in the carbon chain. As the branching increases,the surface area of the

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tert-Butyl alcohol

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(C) The boiling point of isomeric alcohols depends on the extent of branching in the carbon chain. As the branching increases,the surface area of the molecule decreases,which reduces the magnitude of van der Waals forces of attraction. Consequently,the boiling point decreases with an increase in branching. Among the given isomers: $n$-Butyl alcohol $(CH_3CH_2CH_2CH_2OH)$ has no branching. Isobutyl alcohol $((CH_3)_2CHCH_2OH)$ has one branch. sec-Butyl alcohol $(CH_3CH_2CH(OH)CH_3)$ has one branch. tert-Butyl alcohol $((CH_3)_3COH)$ has the maximum branching (three methyl groups attached to the central carbon). Therefore,tert-Butyl alcohol has the lowest boiling point.

Which among the following isomers of $C_4H_9OH$ has the lowest boiling point?

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