Which bond angle theta would result in the ma | vedclass

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Question

(A) The resultant dipole moment $\mu_R$ of two individual bond dipoles $\mu$ inclined at an angle $	heta$ is given by the formula: $\mu_R = \sqrt{\mu

Vedclass · Accepted Answer

$	heta = 90^o$

Vedclass · Answer

(A) The resultant dipole moment $\mu_R$ of two individual bond dipoles $\mu$ inclined at an angle $	heta$ is given by the formula: $\mu_R = \sqrt{\mu^2 + \mu^2 + 2 \mu^2 \cos 	heta} = \sqrt{2 \mu^2 (1 + \cos 	heta)}$.As the bond angle $	heta$ increases from $0^o$ to $180^o$,the value of $\cos 	heta$ decreases from $1$ to $-1$.Consequently,the term $(1 + \cos 	heta)$ decreases as $	heta$ increases.Therefore,the dipole moment $\mu_R$ is maximum when $	heta$ is minimum,which is $90^o$ among the given options.

Which bond angle $\theta$ would result in the maximum dipole moment for the triatomic molecule $YXY$?

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