Which branched chain isomer of the hydrocarbo | vedclass

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(B) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for alkanes is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \implies

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Neopentane

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(B) The molecular mass of the hydrocarbon is $72 \ u$. The general formula for alkanes is $C_nH_{2n+2}$.$12n + 1(2n+2) = 72 \implies 14n = 70 \implies n = 5$.Thus,the hydrocarbon is pentane $(C_5H_{12})$.Among the isomers of pentane (n-pentane,isopentane,and neopentane),neopentane $(2,2-	ext{dimethylpropane})$ has all $12$ hydrogen atoms equivalent.Therefore,upon mono-halogenation,it yields only one mono-substituted alkyl halide.$(CH_3)_4C + Cl_2 \xrightarrow{h
u} (CH_3)_3C-CH_2Cl + HCl$.

Which branched chain isomer of the hydrocarbon with molecular mass $72 \ u$ gives only one isomer of mono-substituted alkyl halide?

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