Which complex shows the highest crystal field | vedclass

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(D) The crystal field splitting energy $(\Delta)$ depends on the oxidation state of the central metal ion and the nature of the ligand. $1$. Higher ox

Vedclass · Accepted Answer

$[Co(NH_3)_6]^{3+}$

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(D) The crystal field splitting energy $(\Delta)$ depends on the oxidation state of the central metal ion and the nature of the ligand. $1$. Higher oxidation state of the central metal ion leads to greater splitting energy. $2$. Strong field ligands (like $NH_3$) cause greater splitting compared to weak field ligands (like $F^-$,$Cl^-$,$H_2O$). $3$. In $[Co(NH_3)_6]^{3+}$,the oxidation state of $Co$ is $+3$ and $NH_3$ is a strong field ligand. $4$. In the other complexes,the oxidation state of $Co$ is $+2$ and the ligands are weaker. Therefore,$[Co(NH_3)_6]^{3+}$ has the highest crystal field stabilisation energy.

Which complex shows the highest crystal field stabilisation energy?

Similar Questions

The crystal field stabilization energy $(CFSE)$ of $[CoF_{3}(H_{2}O)_{3}]$ $(\Delta_{0} < P)$ is $:-$

Write down the number of $3d$ electrons in each of the following ions:
$Ti^{2+}, V^{2+}, Cr^{3+}, Mn^{2+}, Fe^{2+}, Fe^{3+}, Co^{2+}, Ni^{2+}$ and $Cu^{2+}$
Indicate how you would expect the five $3d$ orbitals to be occupied for these hydrated ions (octahedral).

The crystal field splitting energy of $[Co(oxalate)_3]^{3-}$ complex is '$n$' times that of the $[Cr(oxalate)_3]^{3-}$ complex. Here '$n$' is [Assume $\Delta_0 \gg P$].

The number of unpaired electrons in the complex ion $[CoF_6]^{3-}$ is (Atomic number of $Co = 27$).

Which of the following produces high crystal field splitting?

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