Which compound amongst the following is not a | vedclass

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(C) To determine if a compound is aromatic,it must follow $H$ückel's rule: $1$. The molecule must be cyclic. $2$. The molecule must be planar. $3$. Th

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Cyclooctatetraene

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(C) To determine if a compound is aromatic,it must follow $H$ückel's rule: $1$. The molecule must be cyclic. $2$. The molecule must be planar. $3$. The molecule must be fully conjugated. $4$. The molecule must have $(4n + 2) \pi$ electrons,where $n = 0, 1, 2, ...$ Let's analyze each option: - $A$: Cycloheptatrienyl cation has $6 \pi$ electrons $(n=1)$,is cyclic,planar,and conjugated. It is aromatic. - $B$: Cyclopropenyl cation has $2 \pi$ electrons $(n=0)$,is cyclic,planar,and conjugated. It is aromatic. - $C$: Cyclooctatetraene has $8 \pi$ electrons. It is not planar (it adopts a tub shape) and does not follow the $(4n + 2) \pi$ rule. It is non-aromatic. - $D$: Cyclopentadienyl anion has $6 \pi$ electrons $(n=1)$,is cyclic,planar,and conjugated. It is aromatic. Therefore,the compound that is not aromatic is cyclooctatetraene.

Which compound amongst the following is not an aromatic compound?

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