Which gas among the following contains the ma | vedclass

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(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \

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$16.0 \ g$ of $CH_{4}$

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(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \ g}{39.9 \ g \ mol^{-1}} = 0.33 \ mol$ $II. \ n_{O_{2}} = \frac{24.0 \ g}{32 \ g \ mol^{-1}} = 0.75 \ mol$ $III. \ n_{CO_{2}} = \frac{11 \ g}{44 \ g \ mol^{-1}} = 0.25 \ mol$ $IV. \ n_{CH_{4}} = \frac{16.0 \ g}{16 \ g \ mol^{-1}} = 1.0 \ mol$ Since $CH_{4}$ has the maximum number of moles $(1.0 \ mol)$,it contains the maximum number of molecules.

Which gas among the following contains the maximum number of molecules at $STP$? (Molar masses in $g \ mol^{-1}$: $CO_{2}=44, Ar=39.9, CH_{4}=16, O_{2}=32$)

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