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(D) The given reactant is $2,3,5-	ext{trimethylhepta-2,4-diene}$.Upon reductive ozonolysis,the double bonds break to form carbonyl compounds:$1$. The

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$X, Y,$ and $Z$

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(D) The given reactant is $2,3,5-	ext{trimethylhepta-2,4-diene}$.Upon reductive ozonolysis,the double bonds break to form carbonyl compounds:$1$. The first double bond at $C_2-C_3$ yields acetone ($CH_3COCH_3$,$C_3H_6O$) as $X$.$2$. The central part yields methylglyoxal ($CH_3COCHO$,$C_3H_4O_2$) as $Y$.$3$. The terminal double bond yields acetaldehyde ($CH_3CHO$,$C_2H_4O$) as $Z$.Compounds containing the $CH_3CO-$ group or those that can be oxidized to it (like ethanol or acetaldehyde) give a positive iodoform test.- $X$ (Acetone,$CH_3COCH_3$) contains the $CH_3CO-$ group.- $Y$ (Methylglyoxal,$CH_3COCHO$) contains the $CH_3CO-$ group.- $Z$ (Acetaldehyde,$CH_3CHO$) contains the $CH_3CO-$ group.Therefore,all three compounds $X, Y,$ and $Z$ give a positive iodoform test.

Which of the following gives a positive iodoform test? The reaction is shown below:
$2,3,5-\text{trimethylhepta-2,4-diene} \xrightarrow[(2) H_2O/Zn]{(1) O_3} X (C_3H_6O) + Y (C_3H_4O_2) + Z (C_2H_4O)$

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Which of the following gives a positive iodoform test? The reaction is shown below:$2,3,5-\text{trimethylhepta-2,4-diene} \xrightarrow[(2) H_2O/Zn]{(1) O_3} X (C_3H_6O) + Y (C_3H_4O_2) + Z (C_2H_4O)$