Which has the maximum number of molecules amo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of molecules is directly proportional to the number of moles $(n = 	ext{mass} / 	ext{molar mass})$.For $A$: $n(SO_2) = 64 \ g / 64 \

Vedclass · Accepted Answer

$8 \ g \ H_2$

Vedclass · Answer

(D) The number of molecules is directly proportional to the number of moles $(n = 	ext{mass} / 	ext{molar mass})$.For $A$: $n(SO_2) = 64 \ g / 64 \ g \ mol^{-1} = 1 \ mol$.For $B$: $n(CO_2) = 44 \ g / 44 \ g \ mol^{-1} = 1 \ mol$.For $C$: $n(O_3) = 48 \ g / 48 \ g \ mol^{-1} = 1 \ mol$.For $D$: $n(H_2) = 8 \ g / 2 \ g \ mol^{-1} = 4 \ mol$.Since $H_2$ has the highest number of moles $(4 \ mol)$,it contains the maximum number of molecules.

Which has the maximum number of molecules among the following?

Similar Questions

$4.4 \ g$ of $CO_2$ and $2.24 \ L$ of $H_2$ at $\text{STP}$ are mixed in a container. The total number of molecules present in the container will be :

At $STP$,$32 \ g$ of $O_2$ contains $6.022 \times 10^{23}$ molecules. How many atoms does $32 \ g$ of sulfur $(S)$ contain under the same conditions?

The mass of hydrogen (in grams) present in $1.0 \text{ L}$ of pure water of density $1.0 \text{ g cm}^{-3}$ is

Which of the following figures does not represent $1 \ mole$ of $O_2$ gas at $NTP$?

Calculate the number of $Ca^{2+}$ ions in $222 \ g$ of anhydrous calcium chloride $(CaCl_2)$? (Atomic mass: $Ca = 40 \ u$,$Cl = 35.5 \ u$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module