Which ion has tetrahedral geometry:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. In $[Fe(CO)_5]$,the geometry is trigonal bipyramidal ($sp^3d$ hybridization).$2$. In $[Co(NH_3)_6]^{2+}$,the geometry is octahedral ($d^2sp^3

Vedclass · Accepted Answer

$[NiCl_4]^{2-}$

Vedclass · Answer

(C) $1$. In $[Fe(CO)_5]$,the geometry is trigonal bipyramidal ($sp^3d$ hybridization).$2$. In $[Co(NH_3)_6]^{2+}$,the geometry is octahedral ($d^2sp^3$ or $sp^3d^2$ hybridization).$3$. In $[NiCl_4]^{2-}$,$Ni^{2+}$ has a $d^8$ configuration. $Cl^-$ is a weak field ligand,so it does not cause pairing. The hybridization is $sp^3$,resulting in a tetrahedral geometry.$4$. In $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has a $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing. The hybridization is $dsp^2$,resulting in a square planar geometry.Therefore,the correct option is $C$.

Similar Questions

The hybridised orbitals used by silver in the complex $[Ag(NH_3)_2]^+$ are of the type

Which of the following complexes exhibits square planar geometry?

The hybridisation of $Ni$,shape,and number of unpaired electrons present in $[NiCl_4]^{2-}$ are respectively:

Which of the following statements is correct regarding the $[Fe(CN)_6]^{4-}$ complex?

In solid $CuSO_4 \cdot 5H_2O$,copper is coordinated to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module