Which is the correct order of stability for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The stability of oxygen species depends on the bond order and the charge density. The oxide ion $(O^{2-})$ is the most stable due to its closed-sh

Vedclass · Accepted Answer

$Oxide > Peroxide > Superoxide$

Vedclass · Answer

(B) The stability of oxygen species depends on the bond order and the charge density. The oxide ion $(O^{2-})$ is the most stable due to its closed-shell configuration. The peroxide ion $(O_2^{2-})$ has a bond order of $1$,and the superoxide ion $(O_2^-)$ has a bond order of $1.5$. However,in terms of thermodynamic stability in the presence of alkali metals,the order is $Oxide > Peroxide > Superoxide$.

Which is the correct order of stability for the given oxygen species?

Similar Questions

Hydrogen peroxide is stored away from light because it can get decomposed when exposed to light as:

What is the product of the reaction of $H_2O_2$ with $Cl_2$?

Which substance is currently used for the bleaching of paper?

The correct statements among the following are
$i$. Saline hydrides produce $H_2$ gas when reacted with water
$ii$. Presently $\sim 77 \%$ of the industrial dihydrogen is produced from coal
$iii$. Commercially marketed $H_2O_2$ contains $3 \% H_2O_2$

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
${H_2}{\underline{S}}_2{O_8} + {H_2}O \longrightarrow {H_2}S{O_4} + {H_2}O_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module