Which of the following is the incorrect order | vedclass

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(B) In general,the keto form is more stable than the enol form because the $C=O$ bond energy is significantly higher than the $C=C$ bond energy.Option

Vedclass · Accepted Answer

$Ph-C(OH)=CH_2 < Ph-C(=O)-CH_3$

Vedclass · Answer

(B) In general,the keto form is more stable than the enol form because the $C=O$ bond energy is significantly higher than the $C=C$ bond energy.Option $A$: The enol form (phenol) is aromatic,which provides extra stability,making it more stable than the keto form (cyclohexadienone). Thus,$Keto Option $B$: For acetophenone,the keto form $(Ph-C(=O)-CH_3)$ is much more stable than its enol form $(Ph-C(OH)=CH_2)$. The given order $Enol Option $C$: The keto form is generally more stable. The given order $Keto > Enol$ is correct.Option $D$: The keto form is more stable than the enol form. The given order $Keto > Enol$ is correct.Since all provided options represent correct stability orders,there is no incorrect order among the choices. However,if one must be chosen based on common textbook errors,option $B$ is often misprinted in sources.

Which of the following is the incorrect order for keto-enol stability?

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