Which of the following is NOT obtained when m | vedclass

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Question

(A) The hydrolysis of metal carbides yields specific hydrocarbons based on the carbon species present in the carbide lattice.$Al_4C_3$ is a methanide,

Vedclass · Accepted Answer

$Al_4C_3 + H_2O \longrightarrow CH \equiv CH$

Vedclass · Answer

(A) The hydrolysis of metal carbides yields specific hydrocarbons based on the carbon species present in the carbide lattice.$Al_4C_3$ is a methanide,which reacts with water to produce methane: $Al_4C_3 + 12H_2O \longrightarrow 4Al(OH)_3 + 3CH_4$.$CaC_2$ is an acetylide,which produces acetylene: $CaC_2 + 2H_2O \longrightarrow Ca(OH)_2 + C_2H_2$.$Mg_2C_3$ is an allylide,which produces propyne: $Mg_2C_3 + 4H_2O \longrightarrow 2Mg(OH)_2 + CH_3C \equiv CH$.$Be_2C$ is a methanide,which produces methane: $Be_2C + 4H_2O \longrightarrow 2Be(OH)_2 + CH_4$.Therefore,the reaction in option $A$ is incorrect as it produces methane,not acetylene.

Constituents	Percentage
$1$. $CaO$	$a$. $2-3\%$
$2$. $MgO$	$b$. $50-60\%$
$3$. $SiO_2$	$c$. $5-10\%$
$4$. $Al_2O_3$	$d$. $20-25\%$

Which of the following is $NOT$ obtained when metal carbides react with $H_2O$?

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