Which of the following is optically active?

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(D) $1$. $2,2'-dibromo-6,6'-diiodobiphenyl$ is optically active due to restricted rotation around the single bond connecting the two benzene rings (at

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All of the above

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(D) $1$. $2,2'-dibromo-6,6'-diiodobiphenyl$ is optically active due to restricted rotation around the single bond connecting the two benzene rings (atropisomerism) caused by bulky ortho-substituents.$2$. $Butan-2-ol$ $(CH_3CH(OH)CH_2CH_3)$ contains a chiral carbon atom bonded to four different groups,making it optically active.$3$. $N,N-methylethylisopropylammonium \ hydroxide$ contains a chiral nitrogen atom (quaternary ammonium salt) bonded to four different groups,making it optically active.$4$. Since all three compounds are optically active,the correct option is $D$.

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